8x^2+2x-23=-2

Solution for 8x^2+2x-23=-2 equation:

8x^2+2x-23=-2

We move all terms to the left:

8x^2+2x-23-(-2)=0

We add all the numbers together, and all the variables

8x^2+2x-21=0

a = 8; b = 2; c = -21;
Δ = b2-4ac
Δ = 22-4·8·(-21)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-26}{2*8}=\frac{-28}{16}
=-1+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+26}{2*8}=\frac{24}{16}
=1+1/2
$